For `xgeq0` , the smallest value of the function `f(x)=(4x^2+8x+13)/(6(1+x)),` is

For xge 0 , the smallest value of the function f(x)=(4x^2+8x+13)/(6(1+x)) , is ________.

For xge 0 , the smallest value of the function f(x)=(4x^2+8x+13)/(6(1+x)) , is ________.

For x>=0, the smallest value of the function f(x)=(4x^(2)+8x+13)/(6(1+x)), is

For x ge 0 , the smallest value of funcation f(x) = (4x^(2) + 8x + 13)/(6(1 + x)) is

The function f(x)=2+4x^(2)+6x^(4)+8x^(6) has

The function f(x)=2+4x^(2)+6x^(4)+8x^(6) has :

The value of c in the Lagrange's mean value theorem for the function f(x)=x^(3)-4x^(2)+8x+11 , when x in [0, 1] is :

The value of c in the Lagrange's mean value theorem for the function f(x)=x^(3)-4x^(2)+8x+11 , when x in [0, 1] is :

Determine the value of the constant m so that the function f(x)={m(x^2-2x)\ \ \ \ \ if\ x<0,\ \ \ cosx \ \ if\ xgeq0 is continuous.

Let f:R -> ( 0,(2pi)/3] defined as f(x) = cot^-1 (x^2-4x + alpha) Then the smallest integral value of alpha such that, f(x) is into function is