[" If the position vector of a particle is "vec r=(3hat i+4hat j)" meter and its angular velocity "vec omega=(hat j+2hat k)" rad/sec then "],[" its linear velocity is (in "m/s)]

The position vector of a particle is vec( r ) = ( 3 hat( i ) + 4 hat( j )) metre and its angular velocity vec( omega) =(hat( j)+ 2hat( k )) rad s^(-1) then its linear velocity is ( in ms^(-1) )

The position vector of a particle is vec( r ) = ( 3 hat( i ) + 4 hat( j )) metre and its angular velocity vec( omega) =(hat( j)+ 2hat( k )) rad s^(-1) then its linear velocity is ( in ms^(-1) )

The angular velocity of a particle, vec(w) = 3 hat(i) - 4 hat(j) + hat(k) and its position vector, vec( r) = 5 hat(i) - 6 hat(j) + 6 hat(k) . What is the linear velocity of the particle?

The position of a particle is given by vec r = hat i + 2hat j - hat k and its momentum is vec p = 3 hat i + 4 hat j - 2 hat k . The angular momentum is perpendicular to

If the position vectors of vec(A) and vec(B) are 3hat(i) - 2hat(j) + hat(k) and 2hat(i) + 4hat(j) - 3hat(k) the length of vec(AB) is

For a body, angular velocity (vec(omega)) = hat(i) - 2hat(j) + 3hat(k) and radius vector (vec(r )) = hat(i) + hat(j) + vec(k) , then its velocity is :

For a body, angular velocity (vec(omega)) = hat(i) - 2hat(j) + 3hat(k) and radius vector (vec(r )) = hat(i) + hat(j) + vec(k) , then its velocity is :

The position vector of a moving particle at 't' sec is given by vec r=3hat i+4t^(2)hat j-t^(3)hat k .Its displacement during an interval of t =1 s to 3 sec is (A) hat j-hat k (B) 3hat i+4hat j-hat k (C) 9hat i+36hat j-27hat k (D) 32hat j-26hat k