`X` and `Y` are two volatile liquids with molar weights of `10gmol^(-1)` and `40gmol^(-1)` respectively. Two cotton plugs, one soaked in `X` and the other soaked in `Y`, are simultaneously placed at the ends of a tube of length `L=24` cm, as shown in the figure.
The tube is filled with an inert gas at 1 atm pressure and a temperature of `300K`. Vapours of `X` and `Y` react to form a product whichh is first observed at a distance `d`cm from the plug soaked in `X`.
Take `X` and `Y` to have equal molecular diameters and assume ideal behaviour for the inert gas and two vapours.

The value of `d` in cm (shown in figure), as estimated from Graham's law, is

X and Y are two volatile liquids with molar weights of 10gmol^(-1) and 40gmol^(-1) respectively. Two cotton plugs, one soaked in X and the other soaked in Y , are simultaneously placed at the ends of a tube of length L=24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atm pressure and a temperature of 300K . Vapours of X and Y react to form a product whichh is first observed at a distance d cm from the plug soaked in X . Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and two vapours. The experimental value of d is found to be smaller than the estimate obtained using Graham's law. This is due to

Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.

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The weight of one litre of a gas at latm pressure and 300K is 4g. At what temperature the weight of the gas is 4g when the pressure is made 0.5 atm and volume is 1 litre?

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