In the given figure the equation of the line `L_1` is `x/3+y/a=1` and the area of `triangle OAB` is 6 sq units. Then the value of a is equal to

The area bounded by the parabola y=x^(2)+x+1, its tangent at P(1, 3), line x=-1 and the x - axis is A sq units. Then, the value of 6A is equal to

The area bounded by the parabola y=x^(2)+x+1, its tangent at P(1, 3), line x=-1 and the x - axis is A sq units. Then, the value of 6A is equal to

If the area of the triangle with vertices x,0,1,1 and 0,2 1, 4 sq units,then the value of x is :

The area of a triangle with base x unit is equal to the area of a square with sie x sq unit. Then , the altitude of the triangle is

The area of a triangle with base x unit is equal to the area of a square with side x sq unit. Then, the altitude of the triangle is

In the isosceles triangle OAB, O is the origin, OA=OB=6 . If the equation of side AB is x-y+1=0 , then the area of the triangle OAB is (in square units)

The equation of a straight line, perpendicular to 3x-4y=6 and forming a triangle of area 6 sq. units with coordinates axes, is