A solid sphere rolls on a smooth horizontal surface at `10 m//s` and then rolls up a smooth inclined plane of inclination `30^@` with horizontal. The mass of the sphere is `2 kg`. Find the height attained by the sphere before it stops (in `m`).

A uniform solid sphere rolls on a horizontal surface at 20 m/s. It, then, rolls up a plane inclined at

The acceleration of a solid cylinder rolling down an smooth inclined plane of inclination 30° is

A uniform solid sphere rolls on a horizontal surface at 20 ms^(-1) . It then rolls up in incline having an angle of inclination at 30^(@) with the horizontal . If the friction losses are negligible , the value of height h above the ground where the ball stops is

A uniform solid sphere rolls on a horizontal surface with a linear speed of 10 m/s. It then rolls up a.plane inclined at 30° to horizontal. What is the height upto wlrich the sphere rises ? (See Fig.) Assume that the surface is frictionless. Also calculate the distance travelled by the Fig. sphere on the inclined plane ?

A solid sphere of mass m rolls without slipping on an inclined plane of inclination theta . The linear acceleration of the sphere is

A solid spherical ball rolls on a horizontal surface at 10 m/s and continues to roll up on an inclined surface as shown in the figure. If the mass of the ball is 11 kg and frictional losses are negligible, the value of h where the ball stop and starts rolling down the inclination is (Assume g= 10 m//s^2 )