A projectile is projected with a speed of 40m/s at a angle `theta` with horizontal such that `tantheta=(3)/(4)`. After 2 sec, the projectile is moving with speed v at an angle `alpha` with horizontal then, `(g=10m//s^(2))`

A projectile is projected with speed u at an angle theta with the horizontal . The average velocity of the projectile between the instants it crosses the same level is

A projectile is projected with speed u at an angle theta with the horizontal . The average velocity of the projectile between the instants it crosses the same level is

A projectile is projected with a speed u at an angle theta with the horizontal. What is the speed when its direction of motion makes an angle theta//2 with the horizontal

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )

A projectile is fired with a speed u at an angle theta with the horizontal. Find its speed when its direction of motion makes an angle alpha with the horizontal.

A projectile is fired with a speed u at an angle theta with the horizontal. Find its speed when its direcrtion of motion makes an angle alpha with the horizontal.