The function `f :R -> R` satisfies the condition `mf(x - 1) + nf(-x) = 2| x | + 1`. If `f(-2) = 5` and `f(1) = 1` find

The function f:R rarr R satisfies the condition mf(x-1)+nf(-x)=2|x|+1. If f(-2)=5 and f(1)=1 find

The function f: R rarr R satisfies the condition a f(x-1) + b f(-x)=2(|x|+1 . If f(-2)=5 and f(1)=1 , then 8(b-a)= _______

A function f:R rarr R satisfies the condition x^(2)f(x)+f(1-x)=2x-x^(4). Then f(x) is

If the function f(x) satisfies the condition f(x + 1/x) = x^2 + 1/x^2,x ne 0 then f(x) is

A function f : R→R satisfies the equation f(x)f(y) - f(xy) = x + y ∀ x, y ∈ R and f (1)>0 , then

A function y = f(x) satisfies the condition f(x+(1)/x) =x^(2)+1/(x^2)(x ne 0) then f(x) = ........

Function f satisfies the relation f(x)+2f((1)/(1-x))=x AA x in R-{1,0} then f(2) is equal to

Let f be any function defined on R and let it satisfy the condition : | f (x) - f(x) | le ( x-y)^2, AA (x,y) in R if f(0) =1, then :

A polynomial function f(x) satisfies the condition f(x)f((1)/(x))=f(x)+f((1)/(x)) for all x in R,x!=0. If f(3)=-26, then f(4)=