The displacement of a particle performing S.H.M. is given by `x=10 "sin"(omega t+ alpha)` metre. If the displacement of the particle is 5m, then the phase of S.H.M. is

The displacement of a particle performing a S.H.M. is given by x =12 "cos" (omega t + alpha) cm . If at time t, the displacement of the particle is 6 cm, them the phase of the particle at that instant is

The displacement of a particle in S.H.M. is given by x= B "sin" (omega t + alpha) . The initial position (at time t=0), of the particle is the initial phase angle if the angular frequency of the particle is pi rad//s ?

The displacement equation of a particle performing S.H.M. is x = 10 sin (2pit+(pi)/(6)) m. Then the initial displacement of a particle is

The displacement of a particle in S.H.M. is given by x = sinomegat+sqrt(3)cosomegatm . Then at t = 0 its displacement in metres is

The displacement of a particle in S.H.M is in opposite phase with

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is