" 5.Number of electrons in "36mg" of "_(8)^(18)O^(-2)" ions are (Take "N_(A)=6times10^(23)" ) "

Number of electrons in 36mg of ._8^(18)O^(-2) ions are : (Take N_(A) = 6 xx 10^(23))

Number of electrons in 36mg of ._8^(18)O^(-2) ions are : (Take N_(A) = 6 xx 10^(23))

Number of electrons in 1.8 grams of H_(2)O are

Number of electrons present in 3.6 mg of NH_(4)^(+) are : (N_(A) = 6 xx 10^(23))

Number of electrons present in 3.6 mg of NH_(4)^(+) are : (N_(A) = 6 xx 10^(23))

Total number of protons, neutrons and electrons present in 14 mg of ._(6)C^(14) is : (Take N_(A) = 6 xx 10^(23))

" Number of mole of electrons in 8g O^(2-) ions are "