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y=cos(x-(pi)/(4))...

y=cos(x-(pi)/(4))

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Statement -1 The value of determinant |{:(sinpi,cos(x+(pi)/(4)),tan(-(pi)/(4))),(sin(x-(pi)/(4)),-cos((pi)/(2)),In((x)/(y))),(cot((pi)/(4)+x),In((y)/(x)),tan(pi)):}| is zero Statement -2 The value of skew -symetric determinat of odd order equals zero.

If y=e^(x)cos x, prove that (dy)/(dx)=sqrt(2)e^(x)cos(x+(pi)/(4))

If y,=e^(x)cos x, prove that (dy)/(dx),=sqrt(2)e^(x)cos(x+(pi)/(4))

Sketch the graphs of y=cos2x\ a n d\ y=cos(2x-pi/4)\ on the same scale.

Prove that cos((pi)/(4)-x)cos((pi)/(4)-y)-sin((pi)/(4)-x)sin((pi)/(4)-y)=sin(x+y)

Prove that: cos((pi)/(4)-x)cos((pi)/(4)-y)-sin((pi)/(4)-x)sin((pi)/(4)-y)=sin(x+y)

cos((pi)/(4)-x)cos((pi)/(4)-y)-sin((pi)/(4)-x)sin((pi)/(4)-y)=sin(x+y)

The value of cos y cos((pi)/(2)-x)-cos((pi)/(2)-y)cos x+sin y cos((pi)/(2)-x)+cos x sin((pi)/(2)-y) is zero if (A)x=0(B)y=0(C)x=y(D)n pi+y-(pi)/(4)(n in Z)

If x=y cos((2 pi)/(3))=z cos((4 pi)/(3)), then xy+yz+zx=