[(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)],[(7)/((2x+3y))+(4)/((3x-2y)=2],[" For "2x+3y!=0]

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

Sol v e :1/(2(2x+3y))+(12)/(7(3x-2y))=1/2 7/(2x+3y)+4/(3x-2y)=2 where 2x+3y!=0a n d3x-2y!=0.

(1) (5)/(2x)+(2)/(3y)=7,(3)/(x)+(2)/(y)=12

Solve the following pairs of equations by reducing them to a linear pair :- 1/(2(2x+3y))+12/(7(3x-2y))=1/2, 7/(2x+3y)+4/(3x-2y)=2 .

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Solve for x and y if [(x^(2)),(y^(2))]+2[(2x), (3y)]=3[(7),(-3)]

Simplify: (2x+3y)(3x4y)-(7x+3y)(x+2y)

Simplify: (2x+3y)(3x+4y)-(7x+3y)(x+2y)