Home
Class 10
MATHS
गुणनखंड विधि द्वारा समीकरण 1/((x-1)(x-2)...

गुणनखंड विधि द्वारा समीकरण `1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6` को हल कीजिए।

Promotional Banner

Similar Questions

Explore conceptually related problems

1/((x-2)(x-4))+1/((x-4)(x-6))+1/((x-6)(x-8))+1/3=0

Solve: 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6[x!=1,2,3,4]

Solvef or x,(1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

Solve for x : (1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

निम्नलिखित समीकरणों को गुणनखंड विधि द्वारा हल करें- (2x)/(x-3)+1/(2x+3)+(3x+9 )/((x-3)(2x+3))=0

1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)

Long-answer type questions (L.A.) (1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)(xne1,2,3,4)

(2x-1)/(3)+(3x+2)/(2)+7=(1)/(6)+(4x+3)/(6)

(2x-1)/(3)+(3x+2)/(2)+7=(1)/(6)+(4x+3)/(6)