`(x^2y^3+xy)dy=dx`

the solution of (dy)/(dx)(x^(2)y^(3)+xy)=1

(x^(2) y^(3) + 2xy) dy = dx

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1

The solution of dy/dx (x^(2)y^(3)+xy)=1 is -

Solve (x^(3)-3xy^(2))dx+(3x^(2)y-y^(3))dy=0

(3xy+y^(2))dx+(x^(2)+xy)dy=0

(x^(3)+xy^(4))dx+2y^(3)dy=0

(x^(2)-2xy)dy+(x^(2)-3xy+2y^(2))dx=0

Solve the following differential equations (x^3+y^3)dx= (x^2y+xy^2)dy .