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[" Q.4."[" (secA "+tanA" ) "(1-sin A)=],...

[" Q.4."[" (secA "+tanA" ) "(1-sin A)=],[" (a) "sec A," (b) "sin A," (c) "cosec A]" (d) "cos A]

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Prove that : (secA+tanA)(1-sinA)=cosA

Prove that : (secA+tanA)(1-sinA)=cosA

Prove that : (secA+tanA)(1-sinA)=cosA

The value of [(secA+tanA)(1-sinA)] is equal to (a) tan^2A(b)sin^2A (c) cosA (d) sinA

(tanA)/(1+secA) - (tanA)/(1-secA) = 2cosecA

(tanA+secA-1)/(tanA-secA+1)=

Prove that sec A(1-sin A)(secA+tanA)=1 .

(SecA+tanA)(1-sinA) on simplification gives: