If `sec theta+tan theta=lambda` then prove that `(lambda^2-1)/(lambda^2+1)=sin theta`

If sin2A= lambda sin 2B prove that (tan(A+B)/tan(A-B))=(lambda+1)/(lambda-1)

If sin2A= lambda sin 2B prove that (tan(A+B)/tan(A-B))=(lambda+1)/(lambda-1)

If sin2A= lambda sin 2B prove that (tan(A+B)/tan(A-B))=(lambda+1)/(lambda-1)

43.nIf at any place,the angle of dip is theta and magnetic latitude is lambda ,then 1) 2tan theta=tan lambda 2) tan theta=2tan lambda 3) sqrt(3)tan theta=tan lambda 4) tan theta=sqrt(3)tan lambda

If sin2A=lambda sin2B prove that ((tan(A+B))/(tan(A-B)))=(lambda+1)/(lambda-1)

prove that 1+tan theta tan2 theta=sec2 theta

Prove that: (sec theta + tan theta -1)/(tan theta - sec theta +1) = (cos theta)/(1- sin theta)

Prove that (sec theta+tan theta -1)/(tan theta -sec theta +1)=cos theta/(1-sin theta)

Prove that :1+tan theta tan2 theta=sec2 theta