Show that the four points of intersection of the lines : `(2x-y + 1)` `(x-2y+3) = 0`, with the axes lie on a circle and find its centre.

If the four points of intersection of the lines 2x+y-1=0, x+2y+2=0 with the coondinate axes lie on a circle then its centre is

The four point of intersection of the lines ( 2x -y +1) ( x- 2y +3) = 0 with the axes lie on a circle whose center centre is at the point :

The four point of intersection of the lines ( 2x -y +1) ( x- 2y +3) = 0 with the axes lie on a circle whose center centre is at the point :

Find the equation of the circle which passes through the points of intersection of the circle x^(2) + y^(2) + 4(x+y) + 4 = 0 with the line x+y+2 = 0 and has its centre at the origin.

If the 4 points made by intersection of lines 2x-y+1=0, x-2y+3=0 with the coordinate axes are concylic then centre of circle is

If the 4 points made by intersection of lines 2x-y+1=0, x-2y+3=0 with the coordinate axes are concylic then centre of circle is

If a circle passes through the points of intersection of the lines 2x-y +1=0 and x+lambda y -3=0 with the axes of reference then the value of lambda is :

If a circle passes through the points of intersection of the lines 2x-y +1=0 and x+lambda y -3=0 with the axes of reference then the value of lambda is :

Find the points of intersection of the line 2x+3y=18 and the circle x^(2)+y^(2)=25 .