सिद्ध करें कि
`tan (B-C)+ tan (C-A)+ tan (A-B)` `= tan (B-C)* tan (C-A)* tan (A-B)`

Prove that, tan (B - C) + tan (C -A ) + tan (A -B) = tan (B-C) tan (C-A) tan (A -B)

(a) tan A+tan B+tan C=tan A tan B tan C

IF A+B+C =pi , then tan ((A)/(2)) tan ((B)/(2)) + tan (B/2) tan (C/2) + tan (C/2 ) tan ((A)/(2)) is

If tan A+tan B+tan C=tan A . tan B . tan then

If A,B,C are the angles of a triangle, show that, (iv) (tan(B + C) + tan (C + A) + tan (A + B))/(tan (pi - A) + tan(2pi - B) + tan (3pi - C)) = 1

If A+C=B then tan A* tan B * tan C=

tan A+tan B+tan C=

(tan A+tan B-tan C+tan A tan B tan C)/(1-tan A tan B+tan B tan C+tan C tan A)

A + B + C = (pi) / (2) rArr tan A tan B + tan B tan C + tan C tan A =