A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of `3 m s^-2` for `0.5 min`. If the maximum height reached by it is `80 m`, then the angle of projection is `(g = 10 ms^-2)`.

A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of 4 ms^-1 for half a minute. Ir the maximum height reached by it is 180 m, then the angle of projection is (Take g=10 m s^-2 )

If a projectile having horizontal range of 24 m acquires a maximum height of 8 m, then its initial velocity and the angle of projection are

A projectile is thrown with an initial velocity of vecv = (phati+qhatj) m/s. If the range of the projectile is four times the maximum height reached by it, then

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectively. What is the acceleration of the projectile when it reaches its maximum height?