On mixing, heptane and octane form an ideal solution. At `373K` the vapour pressure of the two liquid components (heptane and octane) are `105 kPa` and `kPa` respectively. Vapour pressure of the solution obtained by mixing `25.0` of heptane and `35g` of octane will be (molar mass of heptane `= 100 g mol^(-1)` and of octane `= 114 g mol^(-1))`:-

On mixing, heptane and octane form an ideal solution. At 373K the vapour pressure of the two liquid components (heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 of heptane and 35g of octane will be (molar mass of heptane = 100 g mol^(-1) and of octane = 114 g mol^(-1)) :-

On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressure of the two liquid components ( heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be ( molar mass of heptane = 100 "g mol"^(-1) and of octane = 114 "g mol"^(-1) ):

On mixing , heptane and octane form an ideal solution . At 373 K , the vapour pressures of the two liquid components (heptanes and octane ) are 105 kP_(a) and 45kP_(a) respectively . Vapour pressure of the solution obtained by mixture 25.0 g of heptane and 25 g of octane will be : (Molar mass of heptane -100 g mol^(-1) and of octane = 114 g mol^(-1) )

On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressures ofheptane and octane are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25 g of heptane and 35 g of octane is very close to