A particle moves along a circle of radius R with a constant angular speed `omega`. Its displacement (only magnitude) in time t will be

A particle moves in a circle of radius r with constant angular velocity omega . What is the change in velocity when the particle describe an angle of 90^@ ?

A particle moves along a semicircular path of radius R in time t with constant speed. For the particle calculate

A particle moving along a circule path of radius 'r' with uniform angular velocity omega . Its angular acceleration is

A particles is moving on circular path of radius R with constant angular velocity omega . Its centripetal acceleration will be …... .

A particle is moving in a circle of radius r with constant angular velocity omega . At any point (r, theta ) on its path , its position vector is vec(r ) = r cos theta hat(i) + r sin theta hat(j) . Show that the velocity of the particle has no component along the radius.

If a body is moving in a circle of radius r with a constant speed v m/s. Its angular velocity is

A particle is moving along a circular path of radius 'r' with uniform angular velocity omega . Its angular acceleration is

A particle moves in circle of radius R with a constant speed v. Then, find the magnitude of average acceleration during a time interval (pi R)/(2v) .

A particle moves over three quarters of a circle of radius r . What is the magnitude of its displacement ?