If linear density of a rod of length 3m varies as `lambda = 2 + x,` them the position of the centre of gravity of the rod is

If linear density of a rod of length 3m varies as lamda=2+x , then the position of the centre of mass of the rod is P/7m . Find the value of P.

If the linear density of rod of length 3 m varies as lambda=2+x then the distance of centre of gravity of the rod is………….

If the linear density of a rod of length L varies as lambda = A+Bx , find the position of its centre of mass .

If the linear mass density of a rod of length 3 m (lying from y=0 to y=3 m) varies as lambda =(2+y)kg/m,then position of the centre of mass of the rod from y=0 is nearly at

If the linear mass density of a rod of length 3 m (lying from y=0 to y=3 m) varies as lambda =(2+y)kg/m,then position of the centre of mass of the rod from y=0 is nearly at

The liner density of a rod of length 2m varies as lambda = (2 + 3x) kg/m, where x is distance from end A . The distance of a center of mass from the end B will be

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.