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When sulphur in the form of S(8) is heat...

When sulphur in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1` atm falls by `10%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.

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When sulphur in the form of S_8 is heated at 900k the initial pressure of 1 atm falls by 29% at equilibrium . This is because of conversion of some S_8 "to" S_2 . Find the value of equilibrium constant for this reaction. S_8(g) hArr 4S_2(g)

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When sulphur is heated at 800 K, the initial pressure of 1 atm decreases by 20% at equilibrium K_(p) of the reaction S_(8)(g)rArr4S_(2)(g) is :-

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