ABC is a triangle. `sin((B+C)/(2))=`

A, B and C are interior angles of a triangle ABC, then sin ((B + C)/(2)) =

ABC is a triangle such that sin(2A+B)=sin(C-A)=-sin(B+2C)=1/2 . If A,B, and C are in AP. then the value of A,B and C are..

ABC is a triangle such that sin(2A+B)=sin(C-A)=-sin(B+2C)=1/2 . If A,B, and C are in AP. then the value of A,B and C are..

ABC is a triangle such that sin(2A+B)=sin(C-A)=-sin(B+2C)=1/2 . If A,B, and C are in AP. then the value of A,B and C are:

ABC is a triangle such that sin(2A+B)=sin(C-A)=-sin(B+2C)=1/2 . If A,B, and C are in AP. then the value of A,B and C are..

ABC is a triangle such that sin(2A+B)=sin(C-A)=-sin(B+2C)=(1)/(2)*If(2A, and C are in AP.then the value of A,B and C are..

In any triangle ABC, show that: 2a sin((B)/(2))sin((C)/(2))=(b+c-a)sin((A)/(2))

In a triangle ABC, prove that :a sin((A)/(2)+B)=(b+c)sin((A)/(2))

In a Delta ABC " if " a^(2) sin (B - C) + b^(2) sin (C - A) + c^(2) sin (A - B) = 0 , then triangle is

In a Delta ABC, prove that a sin ((A)/(2) + B) = (b + c) sin ""(A)/(2)