Home
Class 12
CHEMISTRY
The activation energy for the reaction 2...

The activation energy for the reaction `2HI(g)rarrH_(2)+I_(2)(g) " is " 209.5"kJ.mol"^(-1)` at 581K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation. energy ?

Promotional Banner

Similar Questions

Explore conceptually related problems

The activation energy for the reaction : . 2Hl(g) rarr H_(2)(g)+I_(2)(g) is 209.5 kJ mol^(-1) at 581K . Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy ?

The activation energy for the reaction, 2Hi(g) to H_(2)(g) + I_(2)(g) is 209.5 kJ moli^(-1) at 581 K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy.

The activation energy for the reaction 2 HI(g) rarr H_2 + I_2 (g) is 209.5 kJ mol^(-1) at 58IK.Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

The activation energy for the reaction : ltbr. 2Hl(g) rarr H_(2)(g)+I_(2)(g) is 209.5 kJ mol^(-1) at 581K . Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy ?

The activiation energy for the reaction 2HI(g) to H_(2) + I_(2)(g) is 209.5 KJ mol^(-1) at 581 K.Calculate the farction of molecules of reactants having energy equal to or greater than activation energy ?

The activiation energy for the reaction 2HI(g) to H_(2) + I_(2)(g) is 209.5 KJ mol^(-1) at 581 K.Calculate the farction of molecules of reactants having energy equal to or greater than activation energy ?

The activation energy of a reaction 2H I_(g) rarrH_2 + I_(2(g)) is 209.5 kJ mol^-1 at 581K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?