Show that the volume of 1 gram-molecule of any gas at 273K temperature and 1 atm pressure is 22.4 L.

Calculate the volume of 3.6g of water vapour at 273K temperature and 1 atm pressure.

At 273K temp, and 9 atm pressure, the compressibility fog a gas is 0.9 . The volume of 1 mill-moles of gas at this temperature and pressure is :

At 273K temp, and 9 atm pressure, the compressibility fog a gas is 0.9 . The volume of 1 mill-moles of gas at this temperature and pressure is :

At 273 K temperature and 9 atm pressure, the compresibility for a gas is 0.9. The volume of 1 milli- moles of gas at this temperature and pressure is

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

Volume of 0.5 mole of a gas at 1 atm. pressure and 273^@C is

The volume of 0.5 mole of gas at 1 atm pressure and 273^(@)C temperature is

Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.