Solve `1/(1+p^(m-n))+1/(1+p^(n-m))`

Simplify the following: 1/(1+x^(m-n)+x^(m-p))+(1)/(1+x^(n-p)+x^(n-m))+(1)/(1+x^(n-m)+x^(p-n))

Simplify : (1)/(1+x^(m-n)+x^(m-p))+(1)/(1+x^(n-p)+x^(n-m))+(1)/(1+x^(p-m)+x^(p-n)) .

If y=1/(1+x^(n-m)+x^(p-m))+1/(1+x^(m-n)+x^(p-n))+1/(1+x^(m-p)+x^(n-p)) , then (dy)/(dx) is equal to

If y=1/(1+x^(n-m)+x^(p-m))+1/(1+x^(m-n)+x^(p-n))+1/(1+x^(m-p)+x^(n-p)) then (dy)/(dx) at e^m^n^p is equal to: e^(m n p) (b) e^(m n//p) (c) e^(n p//m) (d) none

Solve the followings : (a^(m-n))^(1) xx (a^(n-1))^m xx (a^(1 - m))^(n)

If y=(1)/(1+x^(n-m)+x^(p-m))+(1)/(1+x^(m-n)+x^(p-m))+(1)/(1+x^(m-p)+x^(n-p)) the (dy)/(dx) is

{(P+1/(q))^(m).(p-(1)/(q))^(n)}/{(q+(1)/(p))^(m).(q-(1)/(p))^(n)}

If the sum of m terms of an A.P is equal to these that n terms and also to the sum of the next p terms,prove (m+n)((1)/(m)-(1)/(p))=(m+p)((1)/(m)-(1)/(n))

If the sum of m terms of an A.P. is equal to the sum of either the next n terms or the next p terms, then prove that (m+n)(1/m-1/p)=(m+p)(1/m-1/n)dot