Home
Class 12
CHEMISTRY
[:.V(2)=4V(1)],[" 17."1.8g" of fructose ...

[:.V_(2)=4V_(1)],[" 17."1.8g" of fructose "(C_(6)H_(12)O_(6))" is added to "2kg" of water.The freezing point of solution is "]

Promotional Banner

Similar Questions

Explore conceptually related problems

1.8g of fructose (C_(6)H_(12)O_(6)) is added to 2 kg of water. The freezing point of the solution is

18g glucose (C_(6)H_(12)O_(6)) is added to 178.2g water. The vapour pressure of water (in torr) for this aqueous solution is:

18g glucose (C_(6)H_(12)O_(6)) is added to 178.2g water. The vapour pressure of water (in torr) for this aqueous solution is:

18g glucose ( C_6H_(12)O_6 ) is added to 178.2g water. The vapour pressure of water (in torr) for this aqueous solution is -

18g of glucose (C_(6)H_(12)O_(6)) is added to 178.2g of water. The vapour pressure of water for this aqueous solution at 100^(@)C

18g of glucose (C_(6)H_(12)O_(6)) is added to 178.2g of water. The vapour pressure of water for this aqueous solution at 100^(@)C is-

18g of glucose (C_(6)H_(12)O_(6)) is added to 178.2g of water. The vapour pressure of water for this aqueous solution at 100^(@)C is-

18 g glucose (C_6H_12O_6) is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is.