A block is attached to a spring as shown and very-very gradually lowered so that finally spring expands by 'd'. If same block is attached to spring and released suddenly then maximum expansion in spring will be

When a mass .m. is attached to a vertical spring and slowly released, the extension in the spring is .x.. When a mass .2m. is attached to the same spring and released suddenly, the extension in the spring is

A block of mass m is attached with a spring in vertical plane as shown in the figure. If initially spring is in its natural length and the block is released from rest, then maximum extension in the spring will be

Force constant of a spring is 100 N//m . If a 10kg block attached with the spring is at rest, then find extension in the spring. ( g= 10 m//s^(2) )

As, block of mass 5 kg is attached to spring balance reading of spring balance will be

In a vertical spring mass system, a block of mass m is initially at rest when there is no extension. Now if the mass is released suddenly, then the maximum elongation in the spring is

A block of mass m attached with a spring and held by a person such that the spring is in natural length l_(0) . Now the man releases the block, the ratio of maximum compression in the spring in the given situation , to that of the compression at equilibrium position.

A block of mass 'm' is attached to a spring in natural length of spring constant 'k' . The other end A of the spring is moved with a constat velocity v away from the block . Find the maximum extension in the spring.

To the free end of spring hanging from a rigid support, a block of mass m is hung and slowly allowed to come to its equilibrium position. Then, stretching in the spring is d. If the same block is attached to the same spring and allowed to fall suddenly, the amount of stretching is (force constant k)