In a `DeltaABC,` if median AD is perpendicular to AB, the `tan A+2 tan B` is equal to

In a triangle ABC ,if the median AD through A is perpendicular to AB ,then AD is equal to (A) c tan B B) -ctanA (c) 2c tan A (D) -(c/2)tan A

If the median of DeltaABC through A is perpendicular to AB then tan A+2tanB=

The median AD of a DeltaABC is perpendicular to AB, than tanA + 2tanB=

In a DeltaABC , Median AD perpendicular to side BC . Find the value of tanA/tanB

If the median of a triangle ABC through A is perpendicular to AB then (tan A)/(tan B) has the value equal to

If the median of a triangle ABC through A is perpendicular to AB then (tan A)/(tan B) has the value equal to

If the median of a triangle ABC through A is perpendicular to AB then (tan A)/(tan B) has the value equal to 1) (1)/(2) 2 2 3 -2 4) -(1)/(2)

Prove that DeltaABC is isosceles if median AD is perpendicular to BC.

If DeltaABC is a right angled at C, then tan A + tan B is equal to

The median AD of a Delta ABC is perpendicular to AB,prove that tan A+2tan B=0