समीकरण युग्म `6x -3y+10=0` एवं ` 2x-y+9=0` ग्राफ पर दो रेखाएँ प्रदर्शित करती हैं जो `:`

6x-3y+10=0 2x-y+9=0

6x-3y+10=0,2x-y+9=0

2x+3y=5 6x+9y=10

2x-y-5=0; x+3y-9=0

I. 6x^(2)+x-1=0 II. 8y^(2)+10y+3=0

The equation of the incircle of the triangle formed by the coordinate axes and the line 4x + 3y - 6 = 0 is (A) x^(2) + y^(2) - 6x - 6y - 9 = 0 (B) 4 (x^(2) + y^(2) - x - y) + 1 = 0 (C) 4 (x^(2) + y^(2) + x + y) + 1 = 0 (D) 4 (x^(2) + y^(2) - x - y ) - 1 = 0

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.