यदि वृत्त `x^2+y^2-3x+ky-5=0` और `4x^2+4y^2-12x-y-9=0` संकेन्द्र हों , तो k= …………. .

The circle 4x^(2)+4y^(2)-12x-12y+9=0

The circle 4x^(2)+4y^(2)-12x-12y+9=0

If circles x^(2) + y^(2) - 3x + ky - 5 = 0 " and " 4x^(2) + 4y^(2) - 12x- y - 9 = 0 are concentric , then k =

If the two circle x^(2) + y^(2) - 3x + ky - 5 = 0 and 4x^(2) + 4y^(2) - 12x - y - 9 = 0 are concentric , then : k =

The value of k for which the circles x^2 + y^2 - 3x + ky - 5 = 0 and 4x^2 + 4y^2 - 12x - y - 9 = 0 become concentric is:

The equation of the circle passing through (1/2, -1) and having pair of straight lines x^2 - y^2 + 3x + y + 2 = 0 as its two diameters is : (A) 4x^2 + 4y^2 + 12x - 4y - 15 = 0 (B) 4x^2 + 4y^2 + 15x + 4y - 12 = 0 (C) 4x^2 + 4y^2 - 4x + 8y + 5 = 0 (D) none of these

The equation of the circle passing through (1/2, -1) and having pair of straight lines x^2 - y^2 + 3x + y + 2 = 0 as its two diameters is : (A) 4x^2 + 4y^2 + 12x - 4y - 15 = 0 (B) 4x^2 + 4y^2 + 15x + 4y - 12 = 0 (C) 4x^2 + 4y^2 - 4x + 8y + 5 = 0 (D) none of these

Equation of radical axis of the circles x^(2) + y^(2) - 3x - 4y + 5 = 0 and 2x^(2) + 2y^(2) - 10x - 12y + 12 = 0 is