A cylindrical rod magnet having length of 4 cm and a diameter of 1.2 cm has a uniform magnetization of `4.20 xx 10^(3) A//m^(3)`. Its magnetic dipole moment is

A cylindrical rod magnet has a length of 5 cm and a diameter of 1 cm. It has a uniform magnetization of 5.30xx10^(3) Amp//m^(3) . What is it's magnetic dipole moment?

A Cylindrical magnet has a length of 5cm and a diameter of 1 cm it has a uniform magnetisation of 5.30 xx10^(3) A/m^(3) what is its magnetic dipole moment ?

A cylinderical magnet has a length of 5 cm and a diameter of 1 cm. It has a uniform magnetisation of 5.30 xx 10^3 A//m^3 . What is its magnetic dipole moment ?

A cylindrical magnetic having a length of 7 cm and diameter 4 cm has a uniform magnetization of 6xx10^3 A//m Calculate the dipole moment.

When arod of magnetic material of size 10cm xx 0.5 cm xx 0.2cm is located in magnetizing field of 0.5 xx 10^(4)A/ m then a magnetic moment of 5 Am^(2) is induced in it. Find out the magnetic induction (in. (Wb) / (m)^(2) ) in the rod.

The torque acting on a magnetie dipole of moment 5 A m^(2) when placed in an external uniform magnetic induction 1.5 xx 10^(-4)" Wb/m"^(2) at right angle to magnetic induction is

The torque acting on a magnetie dipole of moment 5 A m^(2) when placed in an external uniform magnetic induction 1.5 xx 10^(-4)" Wb/m"^(2) at right angle to magnetic induction is

Pole strength of a magnet is 5 Am and the magnetic length of it is 10 cm. Calculate the magnetic dipole moment of it.

A circular coil of radius 4 cm having 20 turns carries a current of 3A.It is a magnetic field of intensity 0.5 Wb//m^(2) .The magnetic dipole moment of the coil is