`prod_(j=1)^(n-1)(1-e^(((2 ipi j)/(n))))` is equal to : (where `i=sqrt(-1)`)

prod_(j=1)^(n-1)(1-e^(((2i pi j)/(n)))) is equal to : (where i=sqrt(-1) )

The value of sum_(j=1)^(99)(1)/(1-e^((2 pi i)/(n)j)) is ' a ',then value of [(a)/(20)]

If lim_(n rarr oo)(prod_(k-1)^(n)(1+(k)/(n)))^(1/n) has the value of equal to ke^(-1) where k in N, find k

sum_(i=1)^(oo)sum_(j=1)^(oo)sum_(k=1)^(oo)(1)/(a^(i+j+k)) is equal to (where |a| gt 1 )

1 J//s is equivalent to n erg//s where n is

" If "Lt_(nrarroo) ((prod_(k=1)^(n)(1+(k)/(n))))^(1/n)" has the value of equal to "ke^(-1)" where "k in N" ,then the value of "K" is "

sum_(j=1)^(n)sum_(i=1)^(n)i=

sum_(0<=i