`(3)/(10)+(7)/(10^(2))+(3)/(10^(3))+(7)/(10^(4))+(3)/(10^(5))+(7)/(10^(6))+`

(7)/(10)+(2)/(5)+(3)/(2)=

(7)/(2)+(6)/(10)+(5)/(3)=

Simplify : ((1)/(12) + ((-3)/( 4)) + (7)/(8)) xx (3 (2)/(5) - (7)/(10) + ((-2)/( 15)) - 10 (1)/(30))

(9)/(10)-(3)/(5)+(7)/(8)

[[1,0,-13,4,50,-6,-7]]=[[(1)/(10),(3)/(10),(1)/(5)(21)/(20),-(7)/(20),-(2)/(5)-(9)/(10),(3)/(10),(1)/(5)]]

(7)/(x)+(3)/(5)=(-1)/(10)

The arrangement of rational numbers (-7)/(10),(5)/(-8),(2)/(-3) in ascending order is (2)/(-3),(5)/(-8),(-7)/(10) (b) (5)/(-8),(-7)/(10),(2)/(-3) (c) (-7)/(10),(5)/(-8),(2)/(-3)(d)(-7)/(10),(2)/(-3),(5)/(-8)

5(1)/(7)-{3(3)/(10)-:(2(4)/(5)-(7)/(10))}

Verify the following: (i) ((3)/(4)+(-2)/(5))+(-7)/(10)=(3)/(4)+((-2)/(5)+(-7)/(10)) (ii) ((-7)/(11)+(2)/(-5))+(-13)/(22)=(-7)/(11)+((2)/(-5)+(-13)/(22)) (iii) -1+((-2)/(3)+(-3)/(4))=(-1+(-2)/(3))+(-3)/(4)

The value of 6((1)/(5)) - [4((1)/(2)) - {""((1)/(6)) - (""((3)/(5)) + ""((3)/(10)) - ""((7)/(15)))}] is