Discuss the roles of `Na_2O_2KO_2 and LiOH` in the purification of air.

Na_(2)O_(2) + H_(2)O to

The interaction of O_(3) with potassium hydroxide gives ozonide according to the following equation. underset(168g)(3KOH(s))+2O_(3)(g) to underset(174g)(2KO_(3)(s))+KOH.H_(2)O(s)+(1)/(2)O_(2)(g) The ozonide KO_(3) slowly decomposes to KO_(2) and oxygen underset(174g)(2KO_(3)(s)) to underset(142g)(2KO_(2)(s))+O_(2)(g) The mass of KO_(2) produced by the reaction of 75.0g of KOH is

The oxidation state of K and O in KO_(2) respectively are

Oxidation number(s) of potassium in K_2O , K_2O_2 and KO_2 , respectively, is(are)

Among NO_2^(+),KO_2and Na_2O_2 and NaAlO_2 the paramagnetism exist in -