For the function `f(x)=(log_(e)(1+x)+log_(e)(1-x))/(x)` to be continuous at x = 0, the value of f(0) is

For the function f(x) = (log_(e )(1+x)-log_(e )(1-x))/(x) to be continuous at x = 0, the value of f(0) should be

For the function f(x) = (log_(e )(1+x)-log_(e )(1-x))/(x) to be continuous at x = 0, the value of f(0) should be

If the function f(x)=(log(1+ax)-log(1-bx))/(x) is continuous at x=0, then f(0)=

The value of f(0) for which the function : (log_(e) (1-ax) - log_(3) (1-bx))/(x) is continuous at x = 0 is :

f(x) = ( log (1 +ax ) - log (1 - bx))/(x) is continuous at x = 0 then f(0) =

The function f(x)=((3^x-1)^2)/(sinx*ln(1+x)), x != 0, is continuous at x=0, Then the value of f(0) is

The function f(x)=((3^(x)-1)^(2))/(sin x*ln(1+x)),x!=0, is continuous at x=0, Then the value of f(0) is

The function f(x) = (log(1+ax)-log(1-bx))/x is not defined at x = 0. Find the value of f(0) so that f is continuous at x = 0

If the f(x) =(log(1+ax)-log(1-bx))/x , xne0 is continuous at x = 0 then, f(0) = .....

The functions f(x) = int _0^(1) log_e ((1-x)/(1+x)) dx is