If the equation `(cos p - 1)x^(2) + cos p x + sin p =0` in the varable x has real roots then p can taken any value in the interval

The equaton (cos p - 1) x^(2) + x (cos p ) + sin p = 0 in the veriable x, has real roots then p can take any value in the interval :

The equation (cos p-1)x^(2)+(cos p)x+sin p=0 in the variable x has real roots.The p can take any value in the interval (a) ( 0,2 pi)( b) (-pi,0) (c) (-(pi)/(2),(pi)/(2))( d )(0,pi)

The equation (cosp-1)x^2+(cos p)x+sin p=0 in the variable x has real roots. The p can take any value in the interval (a) (0,2pi) (b) (-pi,0) (c) (-pi/2,pi/2) (d) (0,pi)

The equation (cosp-1)x^2+(cos p)x+sin p=0 in the variable x has real roots. The p can take any value in the interval (a) (0,2pi) (b) (-pi,0) (c) (-pi/2,pi/2) (d) (0,pi)

The equation (cosp-1)x^2+(cos p)x+sin p=0 in the variable x has real roots. The p can take any value in the interval (a) (0,2pi) (b) (-pi,0) (c) (-pi/2,pi/2) (d) (0,pi)

The equation (cos beta-1) x^(2)+(cos beta) x+sin beta=0 in the variable x has real roots, then beta is in the interval

The equation (cos p-1) x^(2) + cos p*x + sin p = 0 where x is a variable, has real roots. Then the interval of possible values of p is