The equivalent weight fo `Na_2S_2O_3` in the reaction `2Na_2S_2O_3 + I_2 rarr Na_2 S_4O_6 + 2 NaI` will be .

Calculate the equivalent weight of Na_2 S_2O_3 for the reaction. 2S_2O_3^(2-) + I_2 rarr S_4O_6^(2-) + 2I

The equivalent weight of Na_(2)S_(2)O_(3) ( Mol. wt = M ) in the reaction , 2Na_(2)S_(2)O_(3) + I_(2) rarr Na_(2) S_(4)O_(6) + 2NaI is-

The equlvalent wt. of Na_(2)S_(2)O_(3) in the reaction, Na_(2)S_(2)O_(3) + H_(2)O + Cl_(2) to Na_(2)SO_(4) + 2HCl + S , is

The equivalent of iodine in the reaction 2Na_(2)S_(2)O_(3)+I_(2)rarr 2NaI+Na_(2)S_(4)O_(6) is [M is molecular weight]

The equivalent weight of hypo in the reaction (M=M" .Wt) \(2Na_{2}S_{2}O_{3}+I_{2} \rightarrow 2NaI+Na_{2}S_{4}O_{6}\) is

The equivalent mass of Na_(2)S_2O_3 as reductant in the reaction, Na_2S_(2)O_(3)+5H_(2)O+4Cl_(2) rarr 2NaHSO_(4) +8HCl