Identify the curve `sqrt((x+1)^(2)+y^(2))+ sqrt(x^(2)+(y-1)^(2))-2`=0

The equation |sqrt(x^(2)+(y-1)^(2))-sqrt(x^(2) +(y+1)^(2))| = k will represent a hyperbola for-

If x ^(2)y^(2) =tan ^(-1) sqrt(x^(2) +y^(2) )+cot ^(-1) sqrt(x^(2) +y^(2)),then (dy)/(dx)=

Equation of a line which is tangent to both the curve y=x^(2)+1 and y=x^(2) is y=sqrt(2)x+(1)/(2) (b) y=sqrt(2)x-(1)/(2)y=-sqrt(2)x+(1)/(2)(d)y=-sqrt(2)x-(1)/(2)

An equation of the curve satisfying xdy - ydx = sqrt(x^(2) - y^(2))dx and y(1) = 0 is

An equation of the curve satisfying x dy - y dx = sqrt(x^(2)-y^(2))dx and y(1) = 0 is

An equation of the curve satisfying x dy - y dx = sqrt(x^(2)-y^(2))dx and y(1) = 0 is

An equation of the curve satisfying x dy - y dx = sqrt(x^(2)-y^(2))dx and y(1) = 0 is

" 24.Show that the equation of tangent at the point "P(x_(1)+y_(1))" on the curve "sqrt(x)+sqrt(y)=sqrt(a)" is "xx_(1)^((-1)/(2))+yy_(1)^((-1)/(2))=a^((1)/(2))