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[" (ii) "cos80^(@)+cos40^(@)-cos20^(@)+s...

[" (ii) "cos80^(@)+cos40^(@)-cos20^(@)+sin50^(@)=sin70^(@)+sin80^(@)],[" (iv) "cos20^(@)+cos100^(@)+cos140^(@)=0]

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cos 20^(@) cos 40^(@) cos 80^(@)=

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))=?

cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=

cos20^(@)cos40^(@)cos60^(@)cos80^(@)=

cos20 ^ (@) cos40 ^ (@) cos80 ^ (@) =

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))=

(sin70^(@)+cos40^(@))/(cos70^(@)+sin40^(@))=

cos20^(@).cos40^(@).cos60^(@).cos80^(@) is :