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The position vector of a particle of mas...

The position vector of a particle of mass m= 6kg is given as `vec(r)=[(3t^(2)-6t) hat(i)+(-4t^(3)) hat(j)] m`. Find:
(i) The force `(vec(F)=mvec(a))` acting on the particle.
(ii) The torque `(vec(tau)=vec(r)xxvec(F))` with respect to the origin, acting on the particle.
(iii) The momentum `(vec(p)=mvec(v))` of the particle.
(iv) The angular momentum `(vec(L)=vec(r)xxvec(p))` of the particle with respect to the origin.

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