Family of lines represented by the equation `(costheta + sintheta)x + (costheta – sintheta)y - 3(3 costheta + sintheta) =0` passes through a fixed point M for all real values of `theta`. The reflection of M in the line `x-y=0`, is-

Family of lines represented by the equation (cos theta+sin theta)x+(cos theta sin theta)y-3(3cos theta+sin theta)=0 passes through a fixed point M for all real values of theta The reflection of M in the line x-y=0, is-

For all value of theta , the lines represented by the equation (2costheta+3sin theta)x+(3costheta-5sintheta)y-(5costheta-2sintheta)=0

Prove that all lines represented by the equation (2costheta+3sintheta)x+(3costheta-5sintheta)y=5costheta-2sintheta …(1) pass through a fixed point and its reflection in the line x+y=sqrt2 ? Prove that all lines through reflection point can be represented by the equation (2costheta+3sintheta)x+(3costheta-5sintheta)y= (sqrt2-1)(5costheta-2sintheta) ....(2)

Eliminate theta,if x=2 costheta-3sintheta y= costheta+2sintheta

Eliminate theta and phi x costheta+y sintheta=a , y costheta-x sintheta=b

If (sintheta)/(x)=(costheta)/(y) then sintheta-costheta is equal to

Eliminate theta x=a sintheta , y=a costheta

If 3 cot theta =4, " write the value of " ((2costheta+ sintheta ))/((4costheta- sintheta)).

Given x^2=cos2theta Show that tan^-1((costheta+sintheta)/(costheta-sintheta))=pi/4+theta

The solution of the equation |(costheta,sintheta,costheta),(-sintheta,costheta,sintheta),(-costheta, -sintheta,costheta)|=0 is -