Repeated observations in an experiment gave the values `1.29 , 1.33 , 1.34 , 1.35 , 1.32 , 1.36, 1.30, and 1.33`. Calculate the mean value, absolute eror , relative error, and percentage error.

The refractive, index of water is found to be the values 1.29, 1.33,1.34, 1.35, 1.3, 1.36,1.30 and 1.33. Calculate the mean values, absolute errors relative error and percentage of error.

The refractive index of water as measured by the relation mu = ("Real depth")/("Apparent depth") was found to have the values 1.29 , 1.33 , 1.34 , 1.35 , 1.32 , 1.36 , 1.30 , 1.33 . Calculate (i) mean value of mu (ii) mean value of absolute error (iii) relative error (iv) percentage error .

If refractive measure of water are 1.32,1.33,1.34, 1.35 and 1.36 then find of absolute error, relative error and percentage error.

The refractive index of water as measured by the relation p = (Real depth)/ (Apparent depth) was found to have the values 1.29, 1.33, 1.34, 1.35, 1.32, 1.36, 1.30, 1.33. Calculate mean value of p.

In ohm's experiment, the values of unknown resistances were found to be 6.12 Omega , 6.15 Omega , calculate the mean absolute error, relative error and percentage error in these measurements.

In an experiment the refractive index of glass was observed to be 1.45 , 1.56 , 1.54 , 1.44 , 1.54 , and 1.53 . Calculate (a). Mean value of refractive index (b). Mean absolute error ( c ) Fractional error (d) Percentage error (e) Express the result in terms of absolute error and percentage error

In an experiment the refractive index of glass was observed to be 1.45 , 1.56 , 1.54 , 1.44 , 1.54 , and 1.53 . Calculate (a). Mean value of refractive index (b). Mean absolute error ( c ) Fractional error (d) Percentage error (e) Express the result in terms of absolute error and percentage error

In an experiment refractive index of glass was observed to be 1.45, 1.56, 1.54, 1.44, 1.54 and 1.53. The mean absolute error in the experiement is