An `alpha` paritcle carrying an electric charge `3.2 xx 10^(-19)C` is at a distance of `13.8 xx 10^(15)m` from a gold nucleus (atomic number=79). Calculate the fore exertedby the gold nucleus on the `alpha` particle.

alpha - particle having 27 MeV has 1.14xx10^(-14) m distance of closest approach from a nucleus of atom. Calculate atomic no. of atom.

An alpha -particle after passing through a potential difference of 2 xx 10^(6) V falls on a silver foil. The atomic number of silver is 47. Calculaye (i) the kinetic energy of the alpha -particle at the time of falling on the foil (ii) the kinetic energy of the alpha -particle at a distance of 5 xx 10^(-14) m from the nucleus and (iii) the shortest distance from the nucleus of silver to which the alpha -particle reaches.

The distance of closest approach of an alpha particle to the nucleus of gold is 2.73 xx 10^(-14) m. Calculate the energy of the alpha particle.

A n alpha -particle of velocity 1.6xx10^(7) m s^(-1) approaches a gold nucleii (Z=79) . Calculate the distance of closest approach. Mas of an alpha -particle =6.6xx10^(-27) kg .

Nucleus ._(92)U^(238) emits alpha -particle (._(2)He^(4)) . alpha- particle has atomic number 2 and mass number 4. At any instant alpha- particle is at distance of 9 xx 10^(-15)m from the centre of nucleus of uranium. What is the force on alpha- particle at this instant? ._(92)U^(238) rarr ._(2)He^(4) + ._(90)Th^(234)

Nucleus ._(92)U^(238) emits alpha -particle (._(2)He^(4)) . alpha- particle has atomic number 2 and mass number 4. At any instant alpha- particle is at distance of 9 xx 10^(-15)m from the centre of nucleus of uranium. What is the force on alpha- particle at this instant? ._(92)U^(238) rarr ._(2)He^(4) + ._(90)Th^(234)

An alpha particle of K.E. 10^(-12)J exibits back scattering form a gold nucleus Z=79. What can be the maximum possible radius of the gold nucleus?