The acceleration of a particle which is depend on time is given by following function a = 2t + 1 and at time t = 0, x = 1m and ui = 2m/s. Then find out displacement of the particle at t = 3 sec.

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The acceleration a of alpha of a particle depends on displacements covered in a time t as a= S + 5 . It is given that initially S=0 m and v=5m//s . Then

The acceleration of a particle is given by a = 3t and at t = 0, v = 0, x = 0. The velocity and displacement at t = 2 sec will be-

The displacement of a particle at time t is given by s= 2 t^3 - 5 t^2 + 4t -3. Find the time when the acceleration is 14 ft/ sec^2 , find the velocity and the displacement at that time.

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the velocity at t=2 sec

The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.

If velocity is depend on time such that v = 4 – 2t. Find out distance travelled by particle from 1 to 3 sec

For a particle displacement (x) and time (t) are related by the following equation : x = (3t^(2)+2t+5) m. If time is expressed in second, find the initial velocity of the particle.