A sphere of `8cm` radius behaves like a black body. It is in thermal equilibrium with the surrounding and absorbs `10 W` of power radiated to it from surrounding. The temperature of the sphere (`sigma=5.67xx10^(-8)W//m^(2)K^(4)`) is approximately.

A sphere of 3 cm radius acts like a black body. If it is in equilibrium with its surrounding and absorb 30 K watt of energy radiated to it from the surrounding. Then the temperature of the sphere will be:

The power of black body at temperature 200 K is 544 W .Its surface area is (sigma=5.67xx10^(-8)Wm^(-2)K^(-2))

A perfectly black sphere of diameter 0.2 m is in thermal equilibrium with the surrounding. What is the temperature of the surrounding, if its rate of absorption of heat energy from the surrounding is 5.67xx4pixx10^(2) watt? [ sigma=5.67xx10^(-8) S.I. units]

The power of a black body at temperature 200K is 544 watt. Its surface area is (sigma = 5.67 xx 10^(-8) wm^(-2) K^(-4))

Calculate the amount of radiation of a black body at 400K temperature. (sigma= 5.67 xx 10^-8 watt//m^2 //k^4)

According to Stefan's law of radiation, a black body radiates energy sigmaT^(4) from its unit surface area every second where T is the surface temperature of the black body and sigma=5.67xx10^(-8)W//m^(2)K^(4) is known as Stefan's constant. A nuclear weapon may be thought of as a ball of radius 0.5 m. When detonated, it reaches temperature of 10^(6) K and can be treated as a black body. Estimate the power it radiates.

According to stefan's law of radiation a black body radiates energy sigmaT^(4) from is unit surface area every second where T is the surface temperature of the black body and sigma = 5.67 xx 10^(-8) W//m^(2) K^(4) is known as Stefan's of as a ball of radius 0.5m When detonated it reaches temperature of 10^(6)K and can be treated as a black body Estimate the power it radiates .

According to Stefan's law of radiation, a black body radiates energy sigmaT^(4) from its unit surface area every second where T is the surface temperature of the black body and sigma=5.67xx10^(-8)W//m^(2)K^(4) is known as Stefan's constant. A nuclear weapon may be thought of as a ball of radius 0.5 m. When detonated, it reaches temperature of 10^(6) K and can be treated as a black body. If surrounding has water at 30^(@)C , how much water can 10% of the energy produced evaporate in 1 s ? [S_(w)=4186.0" J/kg K and "L_(v)=22.6xx10^(5)" J/kg"] .

According to Stefan's law of radiation, a black body radiates energy sigmaT^(4) from its unit surface area every second where T is the surface temperature of the black body and sigma=5.67xx10^(-8)W//m^(2)K^(4) is known as Stefan's constant. A nuclear weapon may be thought of as a ball of radius 0.5 m. When detonated, it reaches temperature of 10^(6) K and can be treated as a black body. If all this energy U is in the form of radiation, corresponding momentum is p=U/c . How much momentum per unit time does it impart on unit area at a distance of 1 km ?

Calculate the amount of radiant energy from a black body at a temperature of (i) 27^(@) C (ii) 2727^(@) C. sigma = 5.67xx10^(-8)Wm^(-2)K^(-4) .