Find k so that the function f(x) defined by
`f(x) = ke^(-3x), x gt 0`
= 0 , otherwise.
is a probability density function.

Show that the function f(x) defined by . f(x) = (1)/(7) , for 1 le x le 8 =0, otherwise, is a probability density function for a random variable. Hence find P(3 lt Xlt 10)

Find k if the function f(x) is defined by f(x)=kx(1-x),"for "0ltxlt1 =0 , otherwise, is the probability density function (p.d.f.) of a random varible (r.v) X. Also find P (Xlt(1)/(2))

If F(x)={{:(kx^(3),0ltxlt2),(0,"otherwise"):} is probability density function find k

Find k, if the function f defined by f(x) = kx, 0 lt x lt 2 =0 , otherwise is the p.d.f of a random variable X.

A function f is defined by f(x^(2) ) = x^(3) AA x gt 0 then f(4) equals

A function f is defined by f(x^(2) ) = x^(3) AA x gt 0 then f(4) equals

A function is defined as f(x) = {(e^x, xle0),(|x-1|, x gt0):} , then f(x) is

If the function f(x) defined by f(x)=(log(1+3x)-log(1-2x))/(x),x!=0 and k

Let a function f be defined by f(x)=(x-|x|)/x for x ne 0 and f(0)=2. Then f is

A function is defined by f(x)=2x-3 Find x such that f(x)=0.