A uniform wire is cut into four segments. Each segment is twice as long as the earlier segment. If the shortest segment has a resistance of `4 Omega`, find the resistance of the original wire.

A uniform wire is cut into four segments. Each segment is twice as long as the earlier segment. If the shortest segment has a resistance of 2 Omega , find the resistance of original wire.

A uniform wire is cut into 10 segments increasing in length in equal steps, the resitance of the shortest segment is R and the resistances of the other segments increase in steps of 8 Omega . If the resistance of the longest segment is 2R, find the value of R and hence find the resistance of the original wire.

A uniform wire is cut 10 segments increasing in length in equal steps. The resistance of shortest segment is R and the resistance of the other segments increases in steps of 4 Omega . If the resistance of the longest segment is 2R, find the value of R and the resistance of original wire.

A uniform wire is cut into two pieces such that on piece is twice as long as the other. The two piece are connected in parallel in the left gap of a meterbridge. When a resistance of 20Omega is connected in the right gap, the null point is obtained at a distance of 60cm from the right end of the wire. Find the resistance of the wire before it was cut into two pieces.

In a balanced metre bridge, the segment of wire opposite to a resistance of 70Omega is 70 cm. The unknown resistance is

In a balanced metre bridge , the segment of wire opposite to a resistance of 70 Omega is 70 cm . The unknown resistance is

Two copper wires have equal length but the thickness of one is twice that of the other. If the resistance of the thin wire is 10 Omega , find the resistance of the thick wire.

A 4 Omega resistance wire is doubled on it. Calculate the new resistance of the wire.