In L-R circuit, resistance is `8Omega` and inductive reactance is `6Omega` then impedance is:

A series AC circuit has a resistance of 4omega and an inductor of reactance 3omega . The impedance of the circuit is z_1 . Now a capacitor of reactance 6omega is connected in the series of above combination, the impedance becomes z_(2) , Then (z_(1))/(z_(2)) will be-

An a.c. circuit contains a resistance of 3 Omega and inductive reactance of 4Omega . The cosine of the phase angle between the current and potential difference in this circuit is

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is

In an A.C. circuit, resistance = 12 Omega and capacitance reactance = 9 Omega are connected in series, then the value of impedance of a circuit will be ..........

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is

A series AC circuit has a resistance of 4 Omega and a reactance of 3 Omega . The impedance of the circuit is

A circuit has a resistance of 11 Omega , an inductive reactance of 25 Omega , and a capacitive resistance of 18 Omega . It is connected to an AC source of 260 V and 50 Hz . The current through the circuit (in amperes) is

A circuit has a resistance of 11 Omega , an inductive reactance of 25 Omega , and a capacitive resistance of 18 Omega . It is connected to an AC source of 260 V and 50 Hz . The current through the circuit (in amperes) is

In a series L-C-R circuit, resistance R = 10 Omega and the impedance Z =20 Omega . The phase = difference between the current and the voltage is .....