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The axis of a parabola is along the line...

The axis of a parabola is along the line y = x and its vertex and focus are in the first quadrant at distances `sqrt2,2sqrt2` respectively, from the origin. The equation of the parabola, is

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The vertex and the focus of a parabola are at distances a and a' respectively form the origin on positive x- axis. The equation of the parabola is

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The axis of a parabola is along the line y=x and the distance of its vertex and focus from the origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is (a) (x+y)^2=(x-y-2) (b) (x-y)^2=(x+y-2) (c) (x-y)^2=4(x+y-2) (d) (x-y)^2=8(x+y-2)

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Find the equation of the parabola whose vertex and focus lie on the y-axis at distance b and b' respectively from the origin.

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt2 and 2 sqrt2 respectively. If vertex and focus both lie in the first quadrant, then find the equation of the parabola

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt2 and 2 sqrt2 respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is :

The axis of a parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt(2) and 2sqrt(2) , respectively. If vertex and focus both lie in the first quadrant, then find equation of the parabola.

The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt2 and 2 sqrt2 respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is :